04-03-2013, 12:20 PM
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Join Date: Apr 2009
Location: Clifton, NJ
Originally Posted by 9Lives
First attempt. I used "amplified diode current". It's where you use a resistor from v+ to the base of a Darlington and 2 series diodes cathode to gnd. Instead of grounding the emitter a capacitor is used. The emitter is then tied to the base of the rf transistors. I attempted to have it switching with the relay.
I wouldn't say fail but, when the circuit was by itself and a 50 ohm load resistor (this maybe my problem) I had .6 v. Perfect!
In circuit I only got .25. Im guessing this is bc of impedance and drive. Coupling capacitor on input of the amp??
im not sure what your trying to build , but the voltage is the applied voltage always , there is no current flowing through it . current drain is in the bias of the transistors. use shockey diodes cause they do not have any voltage drop . is your input unregulated ? and your output is regulated ?