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Texas Star Amplifier Repair

To anybody who stumbles across this thread, that 25-ohm 5-Watt resistor has about 12 Volts DC across it. Should put around one-half Amp through it. 12 Volts times one-half Amp is 6 Watts.

Into a 5-Watt resistor. Nobody checks to see how hot it will be when the amplifier is performing normally. This is the heat it will have to throw when the amplifier is functioning perfectly. Six Watts tends to get a five-Watt resistor pretty toasty.

Pretty much just as hot as when you reach inside trying to pin down a fault.

73
 
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To anybody who stumbles across this thread, that 25-ohm 5-Watt resistor has about 12 Volts DC across it. Should put around one-half Amp through it. 12 Volts times one-half Amp is 6 Watts.

Into a 5-Watt resistor. Nobody checks to see how hot it will be when the amplifier is performing normally. This is the heat it will have to throw when the amplifier is functioning perfectly. Six Watts tends to get a five-Watt resistor pretty toasty.

Pretty much just as hot as when you reach inside trying to pin down a fault.

73

Then why not use a larger resistor? Or maybe parallel two 50 ohm 5 watt resistors?

Am I off track here, or is this a way to reduce the heat and stress?
 
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Yes, a larger resistor reduces temperature, not "heat" the way engineers use the word. Heat can be expressed as Watts. Six Watts of heat will get a 10-Watt resistor too hot to touch, but a 5-Watt part with half that much surface area will exhibit roughly twice the temperature rise for the same wattage.

Doubling the watt rating from 5 to 10 Watts should cut the rise in temperature in half. The "heat" will be determined by the circuit current and resistance alone.

73
 
Last edited:

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