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How does that work when one is an open while its driven into the negative region? Does the base impedance remain low enough to absorb half of the drive? Measuring the DC input power to a push pull pair will prove that both never contribute to the output power simultaneously but I'm still trying to learn about what takes place with the drive power during the negative alternation where one transistor is cutoff.

[QUOTE="Shockwave, post: 676373, member: 10882"] How does that work when one is an open while its driven into the negative region? Does the base impedance remain low enough to absorb half of the drive? Measuring the DC input power to a push pull pair will prove that both never contribute to the output power simultaneously but I'm still trying to learn about what takes place with the drive power during the negative alternation where one transistor is cutoff. [/QUOTE]

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