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So I am guessing that's so it can shift the VCO voltage without dragging the whole PLL around. Please someone correct me if I am wrong or headed in the wrong direction. Trying to learn
In transmit, the tuning voltage comes from the path of the red arrow. In receive, the tuning voltage comes from the path of the green arrow. Clarifier unlocks change that so the clarifier (tuning voltage) is the same in both RX and TX. To do this, it is common to cut off the TX voltage (usually by clipping the diode above the red arrow) and moving the RX voltage source from the RX rail to the 8v (always on) rail. Thats why the wire was moved over to the 8v rail.
Edit: Hold on, I'm having one of my "WTF??" moments. I have a feeling this schematic is wrong, because as is, the course adjustment would work during transmit too (its wiper goes straight to the varactor). This schematic, the 99v, they all show it this way.
I think the schematic should be like this instead (but I've been wrong before):
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