soldering iron temp ??

[1iwilly]

You are not the only one, and you should talk to your primary care doctor, I have been diagnosed with essential tremors, it started several years ago, I found it was getting harder to do fine detail work, soldering is now difficult because of this.
Essential Tremor shakiness is often called an intention or action tremor because it worsens when a person performs some specific task, such as picking up a glass. The most common initial symptom is shaking of the hands, but other areas, including the arms, legs, and head, are frequently involved. Some people develop a trembling voice. At rest or during sleep, the tremor tends to improve or go away.
It's a real thing, not just a symptom of getting old.

73
Jeff

Well because i wanted to do this mod 1st in am all i had was a piece of bread with a couple of sips of coffee. After I did the mod shake was getting worse checked my sugar, i was down to 76. Some OJ, a piece of a candy bar, jump-started me to normal again should of known better to have breakfast 1st nope, my OCD for radio had to be done 1st, LOL

 

[Dr. Frankenstein]

@1iwilly
As the instructions stated "jump 22K (223) resistor with a 4.7K resistor" as you did and was the correct way, but as others stated to jump pins 3 and 4 instead would be wrong ........ because the schematic is wrong.

Looking at and comparing the actual picture of the circuit and the schematic you posted ...... to me looks like the schematic itself is misprinted.
* R1086 = 100K (104), R1087 = 22K (223), R1088 = 47K (473)
* The schematic puts R1087 (22K) & C1092 across pins 3 & 4, with R1086 (100K) going to the capacitor C1082.
* The actual picture that you took of your circuit shows the opposite with R1087 (223/22K) going to capacitor C1082, with R1086 (100K) & C1092 going between pins 3 and 4.

Good job posting a picture of the actual circuit, then following the instructions ....... and not the schematic.

@brandon7861
Did all your calculations, and confusion, get thrown out the window due to going by the (misprinted) schematic? I can understand why you thought a you did due to the misprint.

73

 

[brandon7861]

@1iwilly
As the instructions stated "jump 22K (223) resistor with a 4.7K resistor" as you did and was the correct way, but as others stated to jump pins 3 and 4 instead would be wrong ........ because the schematic is wrong.

Looking at and comparing the actual picture of the circuit and the schematic you posted ...... to me looks like the schematic itself is misprinted.
* R1086 = 100K (104), R1087 = 22K (223), R1088 = 47K (473)
* The schematic puts R1087 (22K) & C1092 across pins 3 & 4, with R1086 (100K) going to the capacitor C1082.
* The actual picture that you took of your circuit shows the opposite with R1087 (223/22K) going to capacitor C1082, with R1086 (100K) & C1092 going between pins 3 and 4.

Good job posting a picture of the actual circuit, then following the instructions ....... and not the schematic.

@brandon7861
Did all your calculations, and confusion, get thrown out the window due to going by the (misprinted) schematic? I can understand why you thought a you did due to the misprint.

73

I just looked closer, and that 22k resistor is to the capacitor! The schematic is indeed wrong. Nice catch! I didn't even think to look that close, I just trusted the schematic. Thank you @Dr. Frankenstein for pointing that out, I thought I was losing my mind when 1iwilly said it worked. I just accepted that I was wrong and moved on lol.

 

[Dr. Frankenstein]

@brandon7861
Would this also mean that the circuit for IC1061 would also be wrong for R1062 (22K) & R1063 (1K)? But that has nothing to do with this thread.

 

[brandon7861]

@brandon7861
Would this also mean that the circuit for IC1061 would also be wrong for R1062 (22K) & R1063 (1K)? But that has nothing to do with this thread.

I am going to guess that the original pic 1iwilly had up before changing it was of that op amp, and that one did show 1k to ground (via cap) in agreement with the schematic. I believe that one is correct. And with 1k on the lower side of the voltage divider, that op-amp is already set up for decent gain.