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X-Force 6 pill getting hot

LOL, first off that's a very poor biasing design. Those 10ohm 20w are there to drop a little voltage and limit current. I would start checking pills and see if they are all good. Then check and make sure each set of pills is getting right voltage. Since that amp has rectifiers, that means it's an unregulated supply. Could be 19-21v floating. Those resistors are working overtime. Lots to look at in that circuit
Crusher, you seem to be the only one to grasp what my question was. I realize the resistors are there to balance the output. I said that in my first post. BUT.........what are the Schottky diodes doing in the input circuit? I have looked at hundreds of amplifiers and hundreds of amp schematics and never seen these diodes at any input to an amplifier. I am politely asking if anyone has seen this and can explain the purpose other than funneling the positive side of the sine wave to ground which could be a considerable amount of current for this type of device. You say it is a very poor design and from what I have seen, I agree. The reason I ask this here is I was told some of the X-Force techs hang out here.
 
I don't like crooks taking people's money by making half assed repairs equipment they know little about...BBI and his youtube videos being a prime example. The only right way for you to do this is learn how an amplifier works. I was hoping you'd ask about some books or learning aids but you want a quick answer to put fast money in your pocket. If you were trying to get your personal amplifier fixed so you can enjoy the hobby I'd love to help you, might even give you parts, but that's obviously not the case here.
I don't want your books, I don't want your parts, and don't want your help. I can spot a wanna-be from a thousand replies away.
 
With the attitude you have I doubt Crusher is going to help you. He works on amps, and I can tell you that most guys that know how to build a good bias circuit aren't going to tell you how they do it. That is why 543 said get your learn on. I am no expert, but I can smell a shithead a mile away and man you sure do stink. Like said, good luck with your endeavors.
 
Well, there you have it. Just ass-uming you know what is going on, ass-uming I have a business, ass-uming I don't know electronics, and ass-summing I am a butt head. If you care to read the very first post I made, it was polite and to the point. Then instead of answering or helping with my question I start getting a bunch of needless cannon fodder that is worthless. Just look at yourselves! You have a forum to help people but as soon as someone asks for help you automatically tell them they need to go read books then come back here and kiss your ass for an answer. The problem is......you don't know what the answer is so you down the person asking to make yourselves look good. Any good moderator would kick Mr. Dallas off the group for the response he made. As for my training, I am a graduate of the University of Kentucky and also of DeVry University. I work in industrial robotics and not in amplifiers. So I am very sorry for interrupting your jerk circle. So post whatever you want, I am out of this useless worldwide dick sucker forum. But there is hope for you as puberty doesn't last forever.
 
Well that was a funny read and it may have left some confusion that could be cleared up. First, the bias detection diode is not a Shottsky diode. They are mostly used for high speed switching. Diodes used for forward bias voltage drop are typically just a simple silicon diode with a forward voltage drop, that is close to the RF transistors emitter / base junction.

Their bias voltage should be injected through a choke and the center tap of the input transformer. That center tap is at RF ground and the choke provides further isolation of the RF and DC bias, so they do not interact or load each other down. If the circuit is properly bypassed, RF won't even know the diode is there. Only the DC component sees the diode.
 

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